DateAdd: Difference between revisions
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''This function is for BASIC compatibility. It is not available in pure JavaScript projects.'' | |||
''' | DateAdd(''interval'',''number'',''date'') | ||
== Description == | |||
''' | DateAdd returns the date which is obtained by adding a specified number of date intervals to a given date. The required parameter, interval, is a string expression that specifies the type of date interval to add: see table below. The required parameter, ''number'', is any numeric expression that specifies the number of intervals to add.The required parameter, ''date'', can be any expression that represents a date. | ||
'''Interval Values''' | |||
{| class="wikitable" | {| class="wikitable" | ||
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|} | |} | ||
== Example (Basic) == | |||
<pre> | <pre> | ||
Rem DateAdd Example | |||
' | 'DateAdd adds date intervals to a date | ||
Print "+10 seconds:", DateAdd("s", 10, NOW) | |||
Print "-1 year:", DateAdd("yyyy", -1, NOW) | |||
</pre> | </pre> | ||
== Output == | |||
<pre> | <pre> | ||
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</pre> | </pre> | ||
== Related Items == | |||
[[datediff|DateDiff]], [[datepart|DatePart]] | |||
[[Category:Language Reference]] | |||
[[Category:Date and Time]] | |||
[[ | [[Category:BASIC Functions]] |
Latest revision as of 15:21, 25 March 2019
This function is for BASIC compatibility. It is not available in pure JavaScript projects.
DateAdd(interval,number,date)
Description
DateAdd returns the date which is obtained by adding a specified number of date intervals to a given date. The required parameter, interval, is a string expression that specifies the type of date interval to add: see table below. The required parameter, number, is any numeric expression that specifies the number of intervals to add.The required parameter, date, can be any expression that represents a date.
Interval Values
Value | Description |
---|---|
yyyy | Year |
q | Quarter |
m | Month |
y | Day of year |
d | Day |
w | Weekday |
ww | Week of year |
h | Hour |
n | Minute |
s | Second |
Example (Basic)
Rem DateAdd Example 'DateAdd adds date intervals to a date Print "+10 seconds:", DateAdd("s", 10, NOW) Print "-1 year:", DateAdd("yyyy", -1, NOW)
Output
+10 seconds: 8/18/98 10:52:54 PM -1 year: 8/18/97 10:52:44 PM