DatePart

DatePart(interval, date[, firstdayofweek[, firstweekofyear]])

Description

DatePart returns a number specifying a part of the given date. The required parameter, interval, determines the part of date which is measured and returned. The optional parameter firstdayofweek is Sunday, if not specified The optional firstweekofyear is the week containing January 1, if not specified.

Example

Rem DatePart Example
'DatePart returns a numberfrompartofadate
Dim QuarterPart, MonthPart, DayPart
QuarterPart = DatePart("q", Now)
MonthPart = DatePart("m", Now)
DayPart = DatePart("d", Now)
Print "Today is day " & DayPart
Print "of month " & MonthPart
Print "in quarter " & QuarterPart

Output

Today is day 18
of month 8
in quarter 3
(''sample output from August 18, 1998'')

Related Items

DateAdd, DateDiff