Instr/InstrRev: Difference between revisions
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Dim Pos1, Pos2 | Dim Pos1, Pos2 | ||
Pos1 = Instr("Cartman", "man") | Pos1 = Instr("Cartman", "man") | ||
Pos2 = InstrRev("Big Al's Big Boat Ride", | Pos2 = InstrRev("Big Al's Big Boat Ride", "big", 4, vbTextCompare) | ||
Print "Finding ""man"" from start:", Pos1 | Print "Finding ""man"" from start:", Pos1 | ||
Print "Finding ""big"" from end:", Pos2 | Print "Finding ""big"" from end:", Pos2 |
Revision as of 10:55, 9 October 2012
Instr([start, ]string1, string2[, compare])
InstrRev(string1, string2[, start[, compare]])
Description
Instr returns a long value specifying the position of one string within another, measured from the start of the string searched.
InstrRev returns a long value specifying the position of one string within another, measured from the end of the string searched.
The optional parameter, start, is a numeric expression that specifies the starting position of the search within the target string. If "start" is not provided, the search defaults to 1, the first character position for Instr, or -1, the last character position for InstrRev. The required parameter, string1, is the string being searched. The required parameter, string2, is the string that is being searched for. The optional parameter, compare, is used to specify the type of search performed. If "string2" is found in "string1", a positive integer is returned with 0 being the location of the first character, otherwise -1 is returned if "string2" is not found in "string1".
Example
Rem Instr/InstrRev finds a string in another Dim Pos1, Pos2 Pos1 = Instr("Cartman", "man") Pos2 = InstrRev("Big Al's Big Boat Ride", "big", 4, vbTextCompare) Print "Finding ""man"" from start:", Pos1 Print "Finding ""big"" from end:", Pos2
Output
Finding "man" from start: 5 Finding "big" form end: 1