Exp: Difference between revisions
Jump to navigation
Jump to search
No edit summary |
No edit summary |
||
Line 5: | Line 5: | ||
Exp returns a double-precision value equal to e<sup>number</sup>. The required parameter, ''number'', is any numeric expression. e is the base of natural logarithms, and is approximately equal to 2.718282. | Exp returns a double-precision value equal to e<sup>number</sup>. The required parameter, ''number'', is any numeric expression. e is the base of natural logarithms, and is approximately equal to 2.718282. | ||
== Example == | == Example (Basic) == | ||
<pre> | <pre> | ||
Line 12: | Line 12: | ||
Print "Exp(0) = " & Exp(0) | Print "Exp(0) = " & Exp(0) | ||
Print "e = " & Exp(1) | Print "e = " & Exp(1) | ||
</pre> | |||
== Example (JavaScript) == | |||
<pre> | |||
// Exp Example | |||
/* Exp raises a number to the eth power */ | |||
NSB.Print("Exp(0) = " + Math.exp(0)); | |||
NSB.Print("e = " + Math.exp(1)); | |||
</pre> | </pre> | ||
Revision as of 18:49, 19 May 2013
Exp(number)
Description
Exp returns a double-precision value equal to enumber. The required parameter, number, is any numeric expression. e is the base of natural logarithms, and is approximately equal to 2.718282.
Example (Basic)
Rem Exp Example 'Exp raises a number to the eth power Print "Exp(0) = " & Exp(0) Print "e = " & Exp(1)
Example (JavaScript)
// Exp Example /* Exp raises a number to the eth power */ NSB.Print("Exp(0) = " + Math.exp(0)); NSB.Print("e = " + Math.exp(1));
Output
Exp(0) = 1 e = 2.718282