DatePart
DatePart(interval, date[, firstdayofweek[, firstweekofyear]])
Description
DatePart returns a number specifying a part of the given date. The required parameter, interval, determines the part of date which is measured and returned. The optional parameter firstdayofweek is Sunday, if not specified The optional firstweekofyear is the week containing January 1, if not specified.
Interval Values
| Value | Description |
|---|---|
| yyyy | Year |
| q | Quarter |
| m | Month |
| y | Day of year |
| d | Day |
| w | Weekday |
| ww | Week of year |
| h | Hour |
| n | Minute |
| s | Second |
Example
Rem DatePart Example
'DatePart returns a numberfrompartofadate
Dim QuarterPart, MonthPart, DayPart
QuarterPart = DatePart("q", Now)
MonthPart = DatePart("m", Now)
DayPart = DatePart("d", Now)
Print "Today is day " & DayPart
Print "of month " & MonthPart
Print "in quarter " & QuarterPart
Output
Today is day 18
of month 8
in quarter 3
(''sample output from August 18, 1998'')