For Each...Next: Difference between revisions

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m Ghenne moved page For each...next to For Each...Next
JwellsNB (talk | contribs)
Add javascript snippet
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Note: For Each...Next will not work with arrays of user-defined types.
Note: For Each...Next will not work with arrays of user-defined types.


== Example ==
== Example (Basic) ==


<pre>
<pre>
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   Print "School employee:", Employee
   Print "School employee:", Employee
Next
Next
</pre>
== Example (JavaScript) ==
<pre>
// For Each...Next Example
var School;
School = new Array("Principal" ,"Mr. Garrison" , "Chef");
for (Employee in School) {
  NSB.Print("School employee: " + School[Employee]);
}
</pre>
</pre>



Revision as of 19:27, 19 May 2013

For Each element In group

[statements]
[Exit For]
[statements]

Next [element]

Description

For Each...Next repeats a group of statements, once for each element in an array or collection. The required parameter, element, is a variable name that can be used to reference the current element. The required parameter, group, is the name of an array, or collection of objects. The optional component, statements, will be executed as the body of the loop. Any number of optional Exit For statements can be used to exit a loop before it is finished. For Each...Next statements can be nested, and any Exit For statements in a nested loop transfer execution to one level above the loop where the Exit For occurs.

Note: For Each...Next will not work with arrays of user-defined types.

Example (Basic)

Rem For Each...Next Example
Dim School
School = Array("Principal","Mr. Garrison", "Chef")
For Each Employee In School
  Print "School employee:", Employee
Next

Example (JavaScript)

// For Each...Next Example

var School;
School = new Array("Principal" ,"Mr. Garrison" , "Chef");
for (Employee in School) {
  NSB.Print("School employee: " + School[Employee]);
}

Output

School employee:     Principal
School employee:     Mr. Garrison
School employee:     Chef

Related Items

Do...Loop, Exit, For...Next, While...Wend