Year: Difference between revisions
Jump to navigation
Jump to search
No edit summary |
|||
| Line 1: | Line 1: | ||
''This function is for BASIC compatibility. It is not available in pure JavaScript projects.'' | |||
Year(''date'') | Year(''date'') | ||
| Line 16: | Line 18: | ||
Birthyear = Year("12/27/70") | Birthyear = Year("12/27/70") | ||
Print "YEAR of 12/27/70:", Birthyear | Print "YEAR of 12/27/70:", Birthyear | ||
</pre> | </pre> | ||
Revision as of 17:31, 24 March 2019
This function is for BASIC compatibility. It is not available in pure JavaScript projects.
Year(date)
Description
Year returns an integer, that represents the year of the given date.The required parameter, date, can be any expression that represents a date.
Example (Basic)
Rem Year Example
'Year returns year of a date as an integer
Dim IndepYear, Birthyear
IndepYear = Year("July 4, 1776")
Print "YEAR of July 4, 1776:", IndepYear
Birthyear = Year("12/27/70")
Print "YEAR of 12/27/70:", Birthyear
Output
YEAR of July 4, 1776: 1776 YEAR of 12/27/70: 1970